Question 12075 of 931 · Texas Journeyman Electrician Exam
NEC 2026 standard method, 120/240 V: 1,500 ft2 house, two small-appliance and one laundry circuit, 12 kW range, 5 kW dryer, 4 kW AC (larger than heat), 4,500 W water heater, 1,200 VA dishwasher. What is the calculated load in amperes?
Exactly one answer is correct.
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Correct answer to question 12075
- C: 113.6 A
Explanation
Lighting/SA/laundry 7,500 VA with demand = 4,575 VA; range 8,000; dryer 5,000; AC 4,000; two appliances at 100 % = 5,700 VA. Total 27,275 VA / 240 V = 113.6 A.
More questions: Load Calculations
- 12076A commercial building's 1-year maximum demand is 160 A. Using the NEC 2026 existing installation method, what is the load before new loads are added?
- 12001Using the standard method under the NEC 2026, what general lighting load must be included in the service calculation for a one-family dwelling with 2,400 ft2 of livable floor area?
- 12002A 2,000 ft2 dwelling has the minimum two small-appliance circuits and one laundry circuit. Under the NEC 2026 standard method, what is the demand load for general lighting, small-appliance and laundry loads combined?
- 12003A 3,200 ft2 one-family dwelling has three 20 A small-appliance circuits and one laundry circuit. Under the NEC 2026 standard method, what is the net demand load for these loads plus general lighting?
- 12004Under the NEC 2026 standard method, what is the demand load for general lighting, two small-appliance circuits and one laundry circuit in a 4,500 ft2 dwelling?
- 12005Optional method (NEC 2026): a 2,000 ft2 dwelling has two small-appliance circuits, one laundry circuit, a 12 kW range, a 5 kW dryer, a 1,200 VA dishwasher and a 4,500 W water heater. What is the calculated general load (heating and AC excluded)?